7x^2-242x+663=0

Solution for 7x^2-242x+663=0 equation:

7x^2-242x+663=0

a = 7; b = -242; c = +663;
Δ = b2-4ac
Δ = -2422-4·7·663
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-242)-200}{2*7}=\frac{42}{14}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-242)+200}{2*7}=\frac{442}{14}
=31+4/7
$